I want to initialize a very large character array with the same character string
69 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
The array is so large it takes forever for MATLAB to do it with a simple loop, e.g.;
for i = 1:N A(i) = 'String' end
I know this can be done numerically using ones (* the desired value) in a single line of code. Can it be done with a character string in a way that speeds up the process?
Thanks, David
1 Commento
Risposte (2)
Iain
il 4 Giu 2013
char_array = char(ones(N,1) * 'String');
cell_version = repmat({'String'},N,1);
0 Commenti
Ahmed
il 4 Giu 2013
Have you tried 'repmat'?
N = 100000;
A = repmat('String',N,1);
If you must use a for-loop, you should pre-allocate the array. If uninitialized, the growing of the array will consume a lot of time. Here, an example of preallocation and filling with loop.
N = 100000;
A = repmat(char(0),N,6);
for i = 1:N, A(i,:) = 'String'; end
1 Commento
Jan
il 4 Giu 2013
It is much faster to operate on the columns and assign scalars:
N = 100000;
A = repmat(char(0),N,6);
S = 'String';
for k = 1:6
A(:, k) = S(k);
end
Vedere anche
Categorie
Scopri di più su Characters and Strings in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!