Why fopen does not accept the path when it is assigned to a variable.

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Bilge
Bilge il 7 Giu 2013
filename=['tests/testbkc/result-1/abc.txt']; fid=fopen('filename','w')
Here fid returns bigger than 3 but it does not create any file.
If I wrote the path directly into fopen then everything is okey. But I need to use variable.
what should be the type of filename? Isnt it char?
Does anybody have an idea? Thanks

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Ahmed
Ahmed il 7 Giu 2013
omit the the '' to get the content of the variable filename.
fid=fopen(filename,'w')

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