Convert matrix to Uitable

A matrix is here

U(35)=9;

U(44)=29;

A=[-1,1,1;0,-1,0;0,0,-1;1,0,0];

blnA = logical( A == -1 );

blnOut = find(any(A == -1,2));

max(blnOut);

negcolumn = find(A(max(blnOut),:) == -1);

onerow = find(A(:,negcolumn) == 1);

And i just wanna convert that matrix to uitable. Because i need a given row name and column name. 

f = figure('Position',[10 10 600 600]);

dat = {-1,1,1;0,-1,0;0,0,-1;1,0,0};

cnames = {'18','29','51'};

rnames = {'12','26','35','44'};

t = uitable('Parent',f,'Data',dat,'ColumnName',cnames,... 
            'RowName',rnames,'Position',[10 10 590 590]);

max(blnOut)

ans =

       3

My expected result is 35.

And will use that value 35 like that

U(ans)=?

U(35)

ans = 
     9

If i solve it, My whole calculation will be perfect. Please give me your hand

[Image Analyst]

Why give you a hand here rather than the thousand of other posts on this question that you've posted?

Answer 1

[Image Analyst]

This will do it:

U(35)=9;
U(44)=29;
A=[-1,1,1;0,-1,0;0,0,-1;1,0,0];
blnA = sum( A == -1, 2 )
lastRow = find(blnA, 1, 'last')
f = figure('Position',[10 10 600 600]);
dat = {-1,1,1;0,-1,0;0,0,-1;1,0,0}
columnHeaders = {'18','29','51'};
rowHeaders = {'12','26','35','44'};
t = uitable('Parent',f,'Data',dat,'ColumnName',columnHeaders,... 
            'RowName',rowHeaders,'Position',[10 10 590 590]);
theAnswer = str2double(rowHeaders{lastRow})
% Get that number from U:
finalAnswer = U(theAnswer)

[Walter Roberson]

Though if you are going to do that, why not just use numeric column names and row names?

columnHeaders = {18,29,51};
rowHeaders = {12,26,35,44};

and then

theAnswer = rowHeaders{lastRow};

[Image Analyst]

Yes, that's best, and what I suggested in my other answer in one of Light's duplicate questions (that I didn't delete). The whole intent of the code is just an incomprehensible mess to me - I have no idea what Light wants, and consequently can't suggest a good approach.