Working with a set of matrices

7 visualizzazioni (ultimi 30 giorni)
Lorcan O'Connor
Lorcan O'Connor il 3 Apr 2021
I want to generate a finite matrix group by starting with the S ={identity} and multiplying by some generators until S no longer grows in size.
Is there an efficient way to deal with a "set" like this, without manualling checking for duplicates? For example, it seems awkward if you use cell arrays to store the elements of S.
  2 Commenti
Matt J
Matt J il 3 Apr 2021
For example, it seems awkward if you use cell arrays to store the elements of S.
Why?
Lorcan O'Connor
Lorcan O'Connor il 3 Apr 2021
Well say I multiply everything in the cell array by a matrix and only want to take the new elements, how do I efficiently take a “set Union” (or even check if a matrix is in the array), without just looping and checking everything?

Accedi per commentare.

Risposta accettata

Matt J
Matt J il 3 Apr 2021
Modificato: Matt J il 3 Apr 2021
I'm not sure I will fully understand the task without seeing an example. However, if S is organized as an MxNxP array,
[M,N]=deal(3,3);
S=cat(3,eye(M,N), randi(5,M,N), eye(M,N) )
S =
S(:,:,1) = 1 0 0 0 1 0 0 0 1 S(:,:,2) = 4 5 4 2 1 3 1 5 2 S(:,:,3) = 1 0 0 0 1 0 0 0 1
then you can get rid of duplicate slices with
s=reshape(S,[],size(S,3));
S=reshape( unique(s.','rows').', M,N,[])
S =
S(:,:,1) = 1 0 0 0 1 0 0 0 1 S(:,:,2) = 4 5 4 2 1 3 1 5 2
If S contains non-integer matrices, you will probably need to use uniquetol() instead of unique().

Più risposte (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by