Measure distance and angle of object

hello my friends, I need help and I trust you, the goal is to measure these measurements in an automatic way

[darova]

What about imdistline? Or you have more pictures? Can you upload more?

[Moufid Meddeb]

imdistline does not allow automatic mesurers but if you have a method to do this with imdistline tell me plz.

[Image Analyst]

What do we know about the shape? Is the triangle always in roughly the same location and roughly the same size? Does the shape bulge upwards (like this one does) near the "opening" for all images? Is the bottom always sloping? Can you post two or three more images so we can see what kind of variety we need to plan for? I came up with an algorithm that works for this image but I don't know if it would work for any other image.

[Moufid Meddeb]

the difference between each images are measurements a , b , h and two angle . Yes the triangle always in roughly the same location but not roughly the same size. yes the bottom always sloping. this another image

Answer 1

[darova]

Here is the algorithm

• crop the region 1 and find min/max x

[m,n] = size(step1);
[~,x1] = find(step1(:,1:n/2),1,'last');
[~,x2] = find(step1(:,n/2:n),1,'first');
a_value = x2-x1;

• crop region 2

[~,x] = find(step2);
b_value = x(end) - x(1);

• region 3

[y,~] = find(step3);
h_value = max(y) - min(y);

[Moufid Meddeb]

i found this results with an error in a_value

this is the code used

[darova]

Im sorry, my bed. This the part of the code for step1

[m,n] = size(step1);
[~,x1] = find(step1(:,1:n/2),1,'last');
[~,x2] = n/2 + find(step1(:,n/2:n),1,'first');      % considering half of a section
a_value = x2-x1;

[Moufid Meddeb]

[Image Analyst]

x2 = n/2 + find(step1(:,n/2:n),1,'first');