Storing value outside the loop using reshape function
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    Karanvir singh Sohal
 il 12 Apr 2021
  
    
    
    
    
    Commentato: Karanvir singh Sohal
 il 13 Apr 2021
            Hello everyone!
I was working on some code and I can't  silly I'm doing. Here I have attached my problem in short format. I know its still quite lengthy but please help me out. After hours I'm unable to figure out what I'm doing wrong.
l=[4; 2.8];
[mL,nL]=size(l);
A=[15.0 22.5 30.0 37.5 45.0 52.5 60.0 ]';
for h=1:2
  L=l(h);
  X=[L*100/16 L*100/10];
  XD = A(A>=X(1,1) & A<= X(1,2));
  [mX,nX]=size(XD);
    index = 0;
  for i=1:mX
    index=index+1;
    LL(index)=l(h);
    XDD(index)=XD(i);
  end
  A1 = [reshape(LL,[],1)];
  A2 = [reshape(XDD,[],1)];
  L=[A1 A2]
end
Running the above code gives following output:
L =         4           30
            4         37.5
L =         2.8       22.5
            4         37.5
Desired Output
L =         4           30
            4         37.5
L =         2.8       22.5    
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Risposta accettata
  Stéphane Vaillant
 il 12 Apr 2021
        t seems the variables LL and XDD are uninitialized and so keep their value on the second iteration of the loop. What happens when adding LL=[]; XDD=[]; just under "for h=1:2" ?
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