how to make nxn matrix

40 visualizzazioni (ultimi 30 giorni)
WonJong We
WonJong We il 14 Apr 2021
Commentato: WonJong We il 15 Apr 2021
I want to make nxn matrix by follweing rule
n=input
first and last is 1
how can do it?
This is the original formula.
clc;
n=input
A=(n ; n)???
  2 Commenti
Walter Roberson
Walter Roberson il 14 Apr 2021
Sorry, that image is too faint to read.
WonJong We
WonJong We il 14 Apr 2021
Thank you for the information.
I will change!!

Accedi per commentare.

Risposta accettata

Walter Roberson
Walter Roberson il 14 Apr 2021
n = 7
n = 7
d = ones(1,n-2)/2;
M = zeros(n,n) + diag([0,d],+1) + diag([d,0],-1);
M(1) = 1; M(end) = 1;
M
M = 7×7
1.0000 0 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0.5000 0 0.5000 0 0 0 0 0 0 1.0000
  9 Commenti
Walter Roberson
Walter Roberson il 15 Apr 2021
n=3;
%n=input ('put your n=')
d = ones(1,n-1)/2;
M = zeros(n+1,n+1) + diag([0,d],+1) + diag([d,0],-1);
M(1) = 1; M(end) = 1;
M
M = 4×4
1.0000 0 0 0 0.5000 0 0.5000 0 0 0.5000 0 0.5000 0 0 0 1.0000
T = [sym('T0') ; sym('T',[n 1]) ]
T = 
Tvals = T;
Tvals(1) = 500;
Tvals(n+1) = 300; %Tn is at position n+1
MT = subs(M*T, T, Tvals)
MT = 
eqn = MT == T
eqn = 
sol = solve(eqn)
sol = struct with fields:
T0: [1×1 sym] T1: [1×1 sym] T2: [1×1 sym] T3: [1×1 sym]
sol.T0
ans = 
500
sol.T1
ans = 
sol.T2
ans = 
sol.T3
ans = 
300
WonJong We
WonJong We il 15 Apr 2021
Thank you!

Accedi per commentare.

Più risposte (0)

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by