Intersect for multiple vectors

I have three vectors in a for loop.
A=[1 2 3 7];
B=[2 2 4 6];
C=[1 3 2 5];
D=[];
I want to use intersect so that I will avoid elements that are common for the vectors. Like:
I wonder if there is a function for this? I read about mintersect, but I want to find all elements that exist in more than one vector
for i=1:length(A)
if intersect(A,B) || intersect(A,C) || intersect(B,C)
D(i)=0;
end
else
D(i)=1;
end

4 Commenti

Are you trying to find elements that are common to all vectors? e.g. 2, in this case?
A=[1 2 3 7];
B=[2 2 4 6];
C=[1 3 2 5];
D=intersect(intersect(A,B),C)
There are probably other ways still.
No I want to find elements that are common to at least two vectors. In this case 1, 2, 3
DGM
DGM il 15 Apr 2021
Modificato: DGM il 15 Apr 2021
Something like this?
D=unique([intersect(A,B) intersect(A,C) intersect(B,C)])
and I guess if you wanted to mask off elements in a given vector that were in the set D, you could do that
Dmask=~ismember(A,D)
The show code is not clear.
for i=1:length(A)
if intersect(A,B) || intersect(A,C) || intersect(B,C)
D(i)=0;
end
else % There is no IF for this ELSE ???
D(i)=1;
end
Neither the description in the original question, nor the code matchs the explanation given in the commen: "find elements that are common to at least two vectors"
Please case for asking clear question. The more confusing the question is, the more time you and the answering persons waste with not matching suggestions. You are not a beginner, but the code is for your master thesis.

Accedi per commentare.

 Risposta accettata

Jan
Jan il 15 Apr 2021
Modificato: Jan il 15 Apr 2021
If this is the goal: "find elements that are common to at least two vectors":
A = [1 2 3 7];
B = [2 2 4 6];
C = [1 3 2 5];
V = unique([A, B, C]);
D = V((ismember(V, A) + ismember(V, B) + ismember(V, C)) >= 2)
D = 1×3
1 2 3

Più risposte (0)

Categorie

Scopri di più su Loops and Conditional Statements in Centro assistenza e File Exchange

Prodotti

Release

R2017b

Richiesto:

il 15 Apr 2021

Modificato:

Jan
il 15 Apr 2021

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by