Matrix line by line

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TheDice
TheDice il 20 Apr 2021
Commentato: TheDice il 20 Apr 2021
how can i go through a matrix line by line?
I have this matrix and would like to have the value of a spinner depending on the value.
x = [1:1:5; 6:1:10]

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Walter Roberson
Walter Roberson il 20 Apr 2021
x = [1:1:5; 6:1:10; 11:15; 16:20; 21:25; 26:30; 31:35; [36, 0, -1, nan, nan]];
nrow = size(x,1);
for K = 1 : 5
spin = randi(nrow);
randrow = x(spin,:)
end
randrow = 1×5
11 12 13 14 15
randrow = 1×5
26 27 28 29 30
randrow = 1×5
26 27 28 29 30
randrow = 1×5
11 12 13 14 15
randrow = 1×5
31 32 33 34 35
  3 Commenti
Walter Roberson
Walter Roberson il 20 Apr 2021
It sounds like you want linear indexing, but row by row
x = [1:1:5; 6:1:10; 11:15; 16:20; 21:25; 26:30; 31:35; [36, 0, -1, nan, nan]];
nent = numel(x);
xt = x.';
for K = 1 : 5
spin = randi(nent);
randval = xt(spin);
[spin, randval]
end
ans = 1×2
1 1
ans = 1×2
37 0
ans = 1×2
19 19
ans = 1×2
35 35
ans = 1×2
30 30
The entries in the array happen to all be equal to their index when operating with that scheme, except for the last few, and you can see in my example that indeed it happened to pull out the stored value (0) at index 37
TheDice
TheDice il 20 Apr 2021
Thank you. Is it possible to fill the matrix from top to bottom not from left to right?

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