Converting elements which repeat more than 10 times to 0

Hi there, I have an array (4048x1) full of 1s and -1s. I want change it so that, if there are more than 10 consecutive 1s or 10 consecutive -1s, then the rest of the consecutive elements after the 10 will become 0 (zeros).

Ie, if we have 1 -1 1 1 -1 -1 1 1 1 1 1 1 1 1 1 1 1 1 -1 1 -1 1

we would want 1 -1 1 1 -1 -1 1 1 1 1 1 1 1 1 1 1 0 0 -1 1 -1 1

Thanks

[Sivakumaran Chandrasekaran]

i think u can use sum command for 10 ones... if sum==10 then '0' should be placed.

Answer 1

[Ken Atwell]

I would love to see a vectorized way to do this, but using a loop:

 x=[1 -1 1 1 -1 -1 1 1 1 1 1 1 1 1 1 1 1 1 -1 1 -1 1];
 zeroX = false(size(x));
 for i =11:numel(x)
    xsum = sum(x(i-10:i));
    if xsum>10 || xsum <-10
        zeroX(i) = true;
    end
 end
 x(zeroX) = 0

[Mate 2u]

Thanks, very good!

Answer 2

[Tom]

A = [1 -1 1 1 -1 -1 1 1 1 1 1 1 1 1 1 1 1 1 -1 1 -1 1];
Correct = [1 -1 1 1 -1 -1 1 1 1 1 1 1 1 1 1 1 0 0 -1 1 -1 1];

D = [0 diff(A)]/2; %find split points
C = cumsum(abs(D))+1; %create accumarray subs
M = accumarray(C',A,[], @(x) {x'.*(1:length(x) <= 10)}); %split each section into a cell array and set > 10 to 0
B = [M{:}]; %merge

isequal(Correct,B)

[Ken Atwell]

Ah, the magic of accumarray, thanks for sharing.

In this case, the loop is probably the "better choice", as it runs in under half the time and would use far less memory (no cell arrays)