Azzera filtri
Azzera filtri

compare two vectors then insert missing element

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james sinos
james sinos il 29 Apr 2021
Risposto: Stephen23 il 29 Apr 2021
i have a matrix :
A=[ 1.000 0.5860 0.01403
2.500 0.7395 0.01277
3.500 0.8450 0.01146
4.000 0.8967 0.01173
4.500 0.9476 0.01215
5.000 0.9962 0.01280
6.000 1.0973 0.01367
6.500 1.1398 0.01457
7.000 1.1889 0.01515
8.000 1.2574 0.01915
8.500 1.2816 0.02234
9.500 1.3300 0.02731
10.500 1.3267 0.03649 ]
for the first column let say its
B=[ 1.000
1.500
2.000
2.500
3.500
4.000
4.500
5.000
5.500
6.000
6.500
7.000
7.500
8.000
8.500
9.000
9.500
10.000
10.500]
i want to compare A(:1) with b then insert missing rows to make A(:,1) = b , then perform interpolation for A(:,2) and A(:,3) new rows
thanks
  1 Commento
Chunru
Chunru il 29 Apr 2021
Bq = sort(union(B, A(:,1))); % the query points are from B and A(:,1)
C = interp1(A(:, 1), A(:, 2:end), Bq); % Interpolation
C = [Bq C]; % The result

Accedi per commentare.

Risposte (1)

Stephen23
Stephen23 il 29 Apr 2021
Simpler:
A=[ 1.000 0.5860 0.01403
2.500 0.7395 0.01277
3.500 0.8450 0.01146
4.000 0.8967 0.01173
4.500 0.9476 0.01215
5.000 0.9962 0.01280
6.000 1.0973 0.01367
6.500 1.1398 0.01457
7.000 1.1889 0.01515
8.000 1.2574 0.01915
8.500 1.2816 0.02234
9.500 1.3300 0.02731
10.500 1.3267 0.03649 ];
B = 1:0.5:10.5;
C = interp1(A(:,1),A,B(:))
C = 20×3
1.0000 0.5860 0.0140 1.5000 0.6372 0.0136 2.0000 0.6883 0.0132 2.5000 0.7395 0.0128 3.0000 0.7923 0.0121 3.5000 0.8450 0.0115 4.0000 0.8967 0.0117 4.5000 0.9476 0.0121 5.0000 0.9962 0.0128 5.5000 1.0467 0.0132

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