integral with (sin x)^4

1 visualizzazione (ultimi 30 giorni)
zamri
zamri il 12 Lug 2013
Hi, i'd appreciate if anybody could help.
I am trying to integrate this function from 0 to 0.2985
x = linspace(0,0.2985,1000);
y=1/sqrt((1-power(sin(x),4)\0.0865^2));
simps(x,y)
simps(x,y) is a another function that will calculate the integral of y over x. For some reason, when I change the division of linspace (say from 1000 to 500), the result of the simps(x,y) changes significantly.
I think there is something wrong with the line x = linspace(0,0.2985,1000); I don't know to change that line to what.
function simps(x,y) is verified correct by integrating other functions already. It is integration by simpson rule. I have tried double, quad, quad8 but unsuccessful.

Risposte (1)

Mike Hosea
Mike Hosea il 12 Lug 2013
You have two errors. One, you need 1./sqrt instead of 1/sqrt. Second, you have \0.0865^2 instead of /0.0865^2. Here is how to define an anonymous function.
>> f=@(x)1./sqrt((1-power(sin(x),4)/0.0865^2));
>> integral(f,0,0.2985)
ans =
0.390930321219332
  3 Commenti
zamri
zamri il 12 Lug 2013
ops, I'm sorry, I suppose I'll just try it in 2012a. thanks Sir.
Mike Hosea
Mike Hosea il 12 Lug 2013
You can substitute quad or quadl there in an earlier release. I don't like to use these functions in my answers because QUAD and QUADL are now deprecated. You can also use QUADGK.

Accedi per commentare.

Categorie

Scopri di più su Numerical Integration and Differential Equations in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by