Ploting graph on matlab

Hi I just want to plot this equation on matlab and plot the graph for finding the type of its graph too.

here is my code but it didn't work well:

clc, close all

t = 0:1:100000;

ic = -30000*t.*exp(-5000*t) + 6*exp(-5000*t);

figure(1);clf;

plot(t, ic);

xlabel('\bf\it Time ', 'fontsize', (25)),

ylabel('\bf\it Amplitude', 'fontsize', (25)),

Answer 1

[Star Strider]

The function declines very rapidly, so use a different value for ‘t’ —

% t = 0:1:100000; 
t = linspace(0, 2E-3, 500);
ic = -30000*t.*exp(-5000*t) + 6*exp(-5000*t); 
figure(1)%;clf;
plot(t, ic);
xlabel('\bf\it Time ', 'fontsize', (25)),
ylabel('\bf\it Amplitude', 'fontsize', (25)),

Also, the clf call immediately clears ‘figure(1)’ after creating it. The plot call regenerates it so nothing is actually lost, however it is inefficient to create it, clear it, then create it again.

[cikalekli]

Oh now I get it. I do not know how to thank you a lot...

Let me ask you two questions please;

1- I just tried to set this code with 1 millisecond. Is t = 0:1:100000 showing the time set 1 millisecond?

Or how can I change it for 1 millisecond. I'm really wondering it.

2- Do we call this type of graph as "Underdamped"?

Thank you very much again.

Also, sorry how could we find out this -> t = linspace(0, 2E-3, 500);

Could you explain for me in your free time please? Because I want to really deeply understand also this part too.

Sorry again bothering you with my questions :(

[Star Strider]

As always, my pleasure!

‘1- I just tried to set this code with 1 millisecond. Is t = 0:1:100000 showing the time set 1 millisecond?’

I do not understand what this means. The curve is essentially 0 after 2 ms, assuming that the tine constants of the exponentials are in units of 1/sec.

‘2- Do we call this type of graph as "Underdamped"?’

I would.

‘Also, sorry how could we find out this -> t = linspace(0, 2E-3, 500);’

No worries! I looked at the time constants of the exponentials and then experimented to get a decent-looking plot.

.

[cikalekli]

You clearly demonstrated and answered perfectly all of my questions and I purely understood what you meant.

Yeah, now I've just seen that the curve has been set with 0 to 2ms I got it when you wrote this.

Please take care of yourself and I will continue working on my matlab skills after that :)

Thank you ^_^

[Star Strider]

Thank you!

As always, my pleasure! Please take good care of yourself as well!

You appear to be learning MATLAB quickly!