plotting normal vector in 3d

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Jack_111
Jack_111 il 30 Lug 2013
I have three points P0=[x0,y0,z0], P1=[x1,y1,z1] P2=[x2,y2,z2] and I want to calculate the normal out of them what I did is
normal = cross(P0-P1, P0-P2);
and then I wanted to plot the normal so what I did is,
c = normal + P0 %end position of normal vector
quiver3(P0(1), P0(2), P0(3), c(1), c(2), c(3)); but it didn't work any suggestions please
%......Edited

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Matt Kindig
Matt Kindig il 30 Lug 2013
doc quiver3
  11 Commenti
Matt Kindig
Matt Kindig il 31 Lug 2013
Then what I said above is correct. Your dot product is as close to zero as you'll be able to calculate. In other words, your calculated vector (from the cross product) is as close to normal to the plane as you'll be able to get.
I'm not really sure what else to say. Your code is correct, your answer is correct, and that's that. Read http://docs.oracle.com/cd/E19957-01/806-3568/ncg_goldberg.html for why exact floating-point calculations are not possible with a computer.
Jack_111
Jack_111 il 1 Ago 2013
Thank you for your support

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