how can i do Trapezoidal rule? - error

clc
clear
format long
d = [0.05 0.025 0.0125 0.00625 0.003125];
syms x y
f= 10000.*exp(y)/(1+abs(x)./2) ;
I_t_x = int(f,x,-5,0);
I_t = double(int(I_t_x,y,-2,2))
for i = 1:length(d)
x = -5 : d(i) : 0 ;
y = -2 : d(i) : 2 ;
[X,Y] = meshgrid(x,y);
F = 10000*exp(y)/(1+abs(x)/2) ;
I = trapz(y,trapz(x,F,2))
end

2 Commenti

Jan
Jan il 25 Mag 2021
Please post code as text, because then it can be reused easily to write an answer.
Whenever you mention an error in the forum, post a complete copy of the message. Then the readers can concentrate on solving the problem, instead on investing time in guessing, what the error is. You do have this important information on the screen already, so sharing it is the way to go.
I fixed it.

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 Risposta accettata

Jan
Jan il 25 Mag 2021
Which error message do you get?
This should fail, if x and y are symbolic variables:
[X,Y] = meshgrid(x,y);
And you do not use the output X and Y at all:
F = 10000*exp(y)/(1+abs(x)/2) ;
I = trapz(y,trapz(x,F,2))

5 Commenti

jeaho jang
jeaho jang il 25 Mag 2021
Modificato: jeaho jang il 25 Mag 2021
I want to solve this function with trapezoid rule.
-5 <= x <= 0
-2 <=y <= 2
how can i do?
del x and del y = 0.05 0.025 0.0125 0.00625 0.003125
Torsten
Torsten il 25 Mag 2021
Modificato: Torsten il 25 Mag 2021
In your code, use
F = 10000*exp(Y)./(1+abs(X)/2)
And save the integration results in a vector:
I(i) = trapz(y,trapz(x,F,2))
This modification will also result in an error.
clc
clear
format long
d = [0.05 0.025 0.0125 0.00625 0.003125];
syms x y
f= 10000.*exp(y)/(1+abs(x)./2) ;
I_t_x = int(f,x,-5,0);
I_t = double(int(I_t_x,y,-2,2))
for i = 1:length(d)
x = -5 : d(i) : 0 ;
y = -2 : d(i) : 2 ;
[X,Y] = meshgrid(x,y);
F = 10000*exp(Y)/(1+abs(X)/2);
I(i) = trapz(y,trapz(x,F,2))
end
In the definition of F, I wrote ./, not only /
jeaho jang
jeaho jang il 25 Mag 2021
Modificato: jeaho jang il 25 Mag 2021
Thank you torsten

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