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how can we read and show CT scan files on MATLAB GUI

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Hi Everybody
hope you all are enjoying good health. i took CT of a phantom and files are created in the form of .egsphant. theses are 127X127 with 55 slices. i mean i have 55 files, every file contains 127 rows and 127 columns. 127 rows and 127 columns make one image. i want to show them in MATLAB GUI. i wana open the file and using slider wanan show one by one. any help will be greatly appreciated.
Isa
  2 Commenti
Matt Kindig
Matt Kindig il 12 Ago 2013
Modificato: Matt Kindig il 12 Ago 2013
There are a variety of Matlab GUIs that have been created for exactly this purpose. This search on the File Exchange found several. Try a few, and see what you prefer.
Walter Roberson
Walter Roberson il 13 Ago 2013
I do not recognize .egsphant as being DICOM files.

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Jaya Shree
Jaya Shree il 3 Dic 2021
clc; clearall; closeall; I=dicomread('F:\DOI\LIDC-IDRI-0001\1.3.6.1.4.1.14519.5.2.1.6279.6001.298806137288633453246975630178\1.3.6.1.4.1.14519.5.2.1.6279.6001.179049373636438705059720603192\000003.dcm'); info=dicominfo('F:\DOI\LIDC-IDRI-0001\1.3.6.1.4.1.14519.5.2.1.6279.6001.298806137288633453246975630178\1.3.6.1.4.1.14519.5.2.1.6279.6001.179049373636438705059720603192\000003.dcm'); I=dicomread(info); imshow(I,'DisplayRange',[]); title('original image'); % image_gray=rgb2gray(I); image_resize=imresize(I,[256 256]); image_resize=im2double(image_resize); %filtering % B=medfilt2(I,[7 7],'symmetric'); % figure,imshow(B); gamma=0.1;%aspect ratio psi=0;%phase theta=50;%orientation bw=2.8; lambda=3;%wavelength pi=180; for x=1:256 for y=1:256 x_theta=image_resize(x,y)*cos(theta)+image_resize(x,y)*sin(theta); y_theta=image_resize(x,y)*sin(theta)+image_resize(x,y)*cos(theta); gb(x,y)=exp(-(x_theta.^2/2*bw^2+gamma^2*y_theta.^2/2*bw^2))*cos(2*pi/lambda*x_theta+psi); end end figure,
  1 Commento
Walter Roberson
Walter Roberson il 3 Dic 2021
Please use the '>' button to insert formatted code. Because of the % in the code, I cannot tell which parts are intended to be commented or not.
This code does not appear to be an answer to the question that was asked in 2013 ??

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