Can't get string to datetime conversion to work

There seems to be some sort of inconsistency in the converting to datetime code I missed.
q=datetime('2017-05-17 19:36:00', 'InputFormat','yyyy-MM-dd HH:mm:ss')
this works just fine. However, when I am reading the input string '2017-05-17T19:36:00' from an array, stripping the T, and putting it in exactly the same, it fails to work. example:
%data{1}(n) has the string '2019-05-17T19:36:00'
b = strrep(data{1}(n),'T',' ');
disp(b);
%displaying displays 2017-05-17 19:36:00, just like the earlier statement
timestamp = datetime(b,'InputFormat',format);
When I do this, the error message:
Unable to convert '2017-05-17 19:36:00' to datetime using the format 'yyyy-MM-dd HH:mm:ss'.
is displayed. Am i missing something? are these not exactly the same? Thanks for your help.

2 Commenti

could you attach data{1} as a mat file so we can check for odd characters?

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 Risposta accettata

The very first entry in your data{1} has a leading U+FEFF character, which is a unicode Byte Order Mark character, but is to be interpreted as a Zero-Width Non-Breaking Space if it occurs anywhere other than the first position

3 Commenti

how would I go about removing that programmatically? or does it not appear multiple times and i only need to remove it once?
It probably only occurs once, but to be sure, use another strrep to replace char(65279) with empty
Thanks for all your help!

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Più risposte (1)

str = '2019-05-17T19:36:00';
fmt = 'yyyy-MM-dd HH:mm:ss';
b = strrep(str,'T',' ');
disp(b);
2019-05-17 19:36:00
timestamp = datetime(b,'InputFormat',fmt)
timestamp = datetime
17-May-2019 19:36:00
Works for me ?

4 Commenti

I still get the same error when i use your code with str = data {1}(n), so i assume there must be some problem with the data file?
Hi everyone,
I have a similar problem: I like to convert the string
s(1) = "11-Mrz-2025 10:03:47" to datetime using
s1 = datetime(s(1), 'InputFormat', 'dd-MMM-yyyy HH:mm:ss', 'Locale', 'de_DE') and I get the error
Error using datetime (line 257)
Unable to convert '11-Mrz-2025 10:03:47' to datetime using the format 'dd-MMM-yyyy hh:mm:ss' and locale 'de_DE'.
I do not know why this Input Format is not working.
Looks like Mrz is not the "official" short literal month name for March in the de_DE localization
str_en = "11-Mar-2025 10:03:47"
str_en = "11-Mar-2025 10:03:47"
dt = datetime(str_en)
dt = datetime
11-Mar-2025 10:03:47
string(dt,'dd-MMM-uuuu HH:mm:ss',"de_DE")
ans = "11-März-2025 10:03:47"
str = ["11-Mai-2025 10:03:47","11-Okt-2025 10:03:47","11-März-2025 10:03:47"]
str = 1x3 string array
"11-Mai-2025 10:03:47" "11-Okt-2025 10:03:47" "11-März-2025 10:03:47"
datetime(str, "InputFormat", "dd-MMM-uuuu HH:mm:ss", "Locale", "de_DE")
ans = 1x3 datetime array
11-May-2025 10:03:47 11-Oct-2025 10:03:47 11-Mar-2025 10:03:47
Walter Roberson
Walter Roberson il 11 Mar 2025
Modificato: Walter Roberson il 11 Mar 2025
de_DE also uses 'Juni' and 'Juli' instead of 'Jun' and 'Jul'
From a 2017 posting of mine:
Marz = char([77 228 114 122]); %'März' -- but protect in case your system only uses 7 bit characters for .m files
date_strings = regexprep(date_strings, {'Mrz', 'Jun(?=\W)', 'Jul(?=\W)'}, {Marz, 'Juni', 'Juli'}, 'ignorecase');
dates = datetime(date_strings,'InputFormat', 'eee MMM d HH:mm:ss yyyy', 'locale', 'de_DE');

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