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Compare two matrix in matlab

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MCC
MCC il 15 Giu 2021
Commentato: MCC il 15 Giu 2021
I have two matrix data1 and data2. I want to select all rows in data1 that close or equals to data2. I know that loop each element can work but it will take a long time. Is there any easy method I can use?
data1 is attached and data 2 is the following function.
x1 = (0:1:414194)';
data2 = 6*x1;
Thank a lot,
MCC
  1 Commento
SALAH ALRABEEI
SALAH ALRABEEI il 15 Giu 2021
what is the matrices size of data1 and data2!

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SALAH ALRABEEI
SALAH ALRABEEI il 15 Giu 2021
Here you can extract those element val that are in both data located at index1 and index2
[val,index1,index2] = intersect(data1,data2)
  4 Commenti
SALAH ALRABEEI
SALAH ALRABEEI il 15 Giu 2021
Another approach, to find values in a that are close or equal to data in b. Eror 0.001
a=1:10;
b=[3.001,4.99,5,6,10];
[x,y] = meshgrid(a,b);
A = [x(:),y(:)];
index = find(abs(A(:,1)-A(:,2))<1e-3);
x(index) % values in a that are close or equal to data in b
MCC
MCC il 15 Giu 2021
Thanks. This works perfet for my problem.

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Più risposte (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov il 15 Giu 2021
Easy and fast efficient solution is Logical Indexing, e.g.:
IND = Data1==Data2
D1 = Data1(IND);
D2 = Data2(IND);
You can also employ round() fcn to reduce the small differences in values of the two data sets.
Or even better to compute the min. differences and get those indices, e.g.:
[minVal,ClosestIND] = min(abs(Data1-Data2))
D1 = Data1(ClosestIND);
D2 = Data2(ClosestIND);
  3 Commenti
Sulaymon Eshkabilov
Sulaymon Eshkabilov il 15 Giu 2021
In that case, probably a loop would be an opt.
MCC
MCC il 15 Giu 2021
Modificato: MCC il 15 Giu 2021
Yes. Do you have any ideas of how to write this code? The data1 is 47987 by 1 and the data2 is 414195 by 1.
Thanks a lot,
MCC

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