How to convert arc circle plot into binary circle?

 Risposta accettata

R = 1;
th = linspace(0,2*pi,1000) ;
x = R*cos(th) ; y = R*sin(th) ;
xi = linspace(-2,2,100) ;
yi = linspace(-2,2,100) ;
[X,Y] = meshgrid(xi,yi) ;
Z = zeros(100) ;
idx = knnsearch([X(:) Y(:)],[x' y']) ;
Z(idx) = 1 ;
imagesc(Z)

3 Commenti

thank you, and may i know how can i remove the arc that i have shown in the first picture?
Remove the arc?
Change
th = linspace(0,2*pi,1000) ;
to only have the range of angles that you want the arc to cover.

Accedi per commentare.

Più risposte (1)

But for your purpose, instead of using plot(), multiply the coordinates by the resolution you want, and round() them, and then subtract off the minimum x and y . Now you have matrix coordinates.
resolution = 25;
th = linspace(0, 7*pi/9, 500);
r = 5;
xc = 3;
yc = 7;
[x,y] = pol2cart(th, r);
x = x + xc;
y = y + yc;
%the above are data coordinates. Make them into array coordinates.
buffer = 5;
xm = round(x * resolution);
ym = round(y * resolution);
xmin = min(xm);
ymin = min(ym);
xmax = max(xm);
ymax = max(ym);
xmc = xm - xmin + 1 + buffer;
ymc = ym - ymin + 1 + buffer;
arc_image = accumarray([ymc(:), xmc(:)], 1);
imshow(arc_image)

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