Electromotive Force Voltage Example
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    Kutlu Yigitturk
 il 18 Giu 2021
  
    
    
    
    
    Risposto: Mouhamed Niasse
      
 il 18 Giu 2021
            B = [0 0 1]'; v = [0 1 0]'; length = [1 1 1]'; length = length/norm(length);
eVec = cross(v,B); eMag = dot(eVec,length); az = 50; el = 15;
close all;
grn = [0 .8 0]; brn = [.8 .5 0];
Fig = figure; Fig.Position = Fig.Position + [-200 0 100 0];
subplot(1,2,1)
plot3([0 B(1)],[0 B(2)],[0 B(3)],'b','linewidth',3); hold on, grid on
plot3([0 v(1)],[0 v(2)],[0 v(3)],'color',grn,'linewidth',3);
plot3([0 eVec(1)],[0 eVec(2)],[0 eVec(3)],'r','linewidth',3);
text(B(1),B(2),B(3)*1.2,'B','color','b')
text(v(1),v(2)*1.2,v(3),'v','color',grn)
text(eVec(1)*1.0,eVec(2)-.2,eVec(3)+.2,'eVec','color','r')
text(-1.2,-1.5,-1,num2str(B),'color','b'), text(-1.2,-1.5,-.2,'B','color','b'), 
text(-.5,-1.5,-1,num2str(v),'color',grn), text(-.5,-1.5,-.2,'v','color','b'), 
text(0.2,-1.5,-1,num2str(eVec),'color','r'),text(0.2,-1.7,-.2,'eVec','color','r'), 
text(0.9,-1.5,-1,num2str(length,4),'color',brn), text(0.9,-1.6,-.3,'Rod','color',brn)
title('eVec = cross(v,B) eMag = dot(eVec,length)')
set(gca,'color',[1 1 1]*.9)
axis('equal'), axis([-1 1 -1 1 -1 1]*1.5), view(az,el)
Rod0 = [-length length]*0.75; Rod = Rod0 + v*0;
 plot3(Rod(1,:),Rod(2,:),Rod(3,:),'linewidth',6,'color',brn);
 text(Rod(1,1),Rod(2,1),Rod(3,1)+.3,'Rod','color',brn)
 text(Rod(1,2)-.4,Rod(2,2),Rod(3,2)-.3,['eMag = ',num2str(eMag)],'color',brn)
 xlabel('x'), ylabel('y'), zlabel('z')
subplot(1,2,2)
plot3([0 B(1)],[0 B(2)],[0 B(3)],'b','linewidth',1); hold on, grid on
plot3([0 v(1)],[0 v(2)],[0 v(3)],'g','linewidth',1);
plot3([0 eVec(1)],[0 eVec(2)],[0 eVec(3)],'r','linewidth',1);
set(gca,'color',[1 1 1]*.9)
axis('equal'), axis([-1 1 -1 1 -1 1]*2),view(az,el)
 xlabel('x'), ylabel('y'), zlabel('z')
BFldx = [0 0 -.02 .02 0 0 0 0]; BFldy = [0 0 0 0 0 -.02 .02 0]; BFldz = [-1 1 0.9 0.9 1 .9 .9 1]*1.5;
for i = -2:0.5:2
 for j = -2:0.5:2
 plot3(BFldx'+i,BFldy'+j,BFldz','linewidth',0.1,'color',[.5 .5 1]);
 end
end
drawnow
DrawRod = plot3(Rod(1,:),Rod(2,:),Rod(3,:),'linewidth',6,'color',brn);
 TexteMag = text(Rod(1,2)+.1,Rod(2,2)+.1,Rod(3,2)+.1,['+',num2str(eMag)],'color',brn);
Tit = title(['eVec^t = [',num2str([0 0 0]),'] eMag = ',num2str(0)]); 
for n = 1:3
 Rod = Rod0; 
 set(DrawRod,'xdata',Rod(1,:),'ydata',Rod(2,:),'zdata',Rod(3,:));
 set(TexteMag,'pos',Rod(:,2)+.1,'string',num2str(0))
set(Tit,'string',['eVec^t = [',num2str([0 0 0]),'] eMag = ',num2str(0)]), pause(1)
 for m = 0:0.02:1
 eVec = cross(v,B); eMag = dot(eVec,length);
 Rod = Rod0 + v*m; 
 set(DrawRod,'xdata',Rod(1,:),'ydata',Rod(2,:),'zdata',Rod(3,:));
 set(TexteMag,'pos',Rod(:,2)+.1,'string',num2str(eMag))
 set(Tit,'string',['eVec^t = [',num2str(eVec'),'] eMag = ',num2str(eMag)])
 drawnow, pause(0.001)
 end
end
OUTPUT:

What exactly do eVec and e in this code? Thanks for your help.
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  Mouhamed Niasse
      
 il 18 Giu 2021
        Hello,
From the second line of your code, you need to know first what is the physical meaning of each paramaters ('v', 'B', 'length', etc).
eVec = cross(v,B); eMag = dot(eVec,length);
Then you go into MATLAB documentation and read the description of the used functions 'cross' and 'dot'.
Repeat the same process for the rest of the code and you will soon become an expert.
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