How to create a struct

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Chao Zhang
Chao Zhang il 19 Giu 2021
Commentato: Chao Zhang il 20 Giu 2021
There is a simple way to create a struct like the following picture, i.e ROCK = struct('ROCK0', value1, 'ROCK44', value2, 'ROCK50',value3, ....)
I was curious, is there any other ways to create a struct like the above, so i use for loop to do it, and the code is:
for m = 1 : size(rock_code,1)%Assign values to the initial cell
row_index = rock(:,col_ind_rk) == rock_code(m);%determine the row index according to the corresponding rock codes
sub_rock{m} = rock(row_index,:);
end
% Create string for each sub_rock
str_rock = cell(1,size(rock_code,1));%create cell to store strings
for kk = 1 : size(rock_code,1)
str_rock{kk} = sprintf('ROCK%d',rock_code(kk));
end
% Assign strings to each sub_rock
%create struct to store string and values
ROCK = struct;
for ii = 1 : size(rock_code,1)
ROCK = struct(str_rock{1,ii},sub_rock{1,ii});
end
But there is only the name and value of the last rock (i.e. ROCK53) in this structure, so, is there any way to achieve this struct like using for loop or other methods, thanks!
  2 Commenti
Stephen23
Stephen23 il 19 Giu 2021
If you have any choice on the data design, then the best solution is to avoid forcing meta-data into fieldnames and simply use to basic arrays:
data = {1x13,2x13,2x13, .. etc}
rock = [ 0, 44, 50,51,52,53]
This makes processing the (meta-)data simpler and more efficient.
Chao Zhang
Chao Zhang il 20 Giu 2021
Thanks!

Accedi per commentare.

Risposta accettata

Jonas
Jonas il 19 Giu 2021
Modificato: Jonas il 19 Giu 2021
use
for ii = 1 : size(rock_code,1)
ROCK.(str_rock{ii}) = sub_rock{1,ii};
end
at the end if sub_rock cell entries are the values for the fields

Più risposte (1)

Jan
Jan il 19 Giu 2021
str_rock = sprintfc('ROCK%d', rock_code); % Undocumented
ROCK = cell2struct(str_rock(:), sub_rock(:));

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