could anyone help me how to convert double to cell in an array.

I am having a cell array A in the folllowing manner

where A=3x1 cell

1x3 double - [1,1,1]

1x3 double - [1,2,2]

1x3 double - [1,1,2]

now, I want to convert A into B as given below

B=3x1 cell

1x1cell - [1,2,3]

1x2 cell -[1] [2,3]

1x2 cell - [1,2] [3]

i.e.,

A=3x1 cell to B=3x1 cell

1x3 double - [1,1,1] to 1x1cell - [1,2,3]

1x3 double - [1,2,2] to 1x2 cell -[1] [2,3]

1x3 double - [1,1,2] to 1x2 cell - [1,2] [3]

Could anyone please help me on this to do it on a general manner as my cell array size is larger.

[dpb]

To do anything in a "general" manner, there has to be some recognizable pattern that can be used as the basis for the algorithm -- what is the general rule here for an aribtrary size?

[jaah navi]

the pattern for the algorthm is as follows:

A has all rows in double that needs to be converted as cell as shown in each rows of B.

In specific each rows of A has three values for example i am considering the first row of A 1x3 double - [1,1,1] .

Here as all the three values are 1 (in double), it need to be converted to cell as [1,2,3]

For 1x3 double - [1,2,2] the first value is 1 and the second and third value is 2. So to convert, the first value that corresponds to 1 should be [1] and the remaining two values corresponds to 2 should be [2,3].

For 1x3 double -[1,1,2] the first two values are 1 and the third value is 2. So to convert, the value corresponds to first two values should be [1,2] and the third value corresponds to 2 should be [3].

If my explanation is still not clear please let me know.Also please help me on this.

Answer 1

[Matt J]

B=cell(size(A));
for i=1:numel(A)

    B{i}=splitapply(@(x){x}, 1:numel(A{i}) ,A{i});
    
end

[jaah navi]

when I tried your command it results in i=3.

But what I actually need is to convert each rows in A=3x1 cell to B=3x1 cell.

i.e.,

A=3x1 cell B=3x1 cell

1x3 double - [1,1,1] to 1x1cell - [1,2,3]

1x3 double - [1,2,2] to 1x2 cell -[1] [2,3]

1x3 double - [1,1,2] to 1x2 cell - [1,2] [3]

after converting each rows in A should look like the rows in B.

Could you please help me on this.

[Matt J]

I don't understand what you say you are seeing, but we can easily add some lines as below to display the output. It matches what you say you want.

A=[1 1 1 ; 1 2 2; 1 1 2]; A=num2cell(A,2);


B=cell(size(A));
for i=1:numel(A)
    B{i}=splitapply(@(x){x}, 1:numel(A{i}) ,A{i});
    
    disp("A{" +i+ "}:"), A{i}
    for j=1:numel(B{i})
    disp("B{" +i+ "}{"+j+"}:"), B{i}{j}
    end
    disp ' '
end

A{1}:

ans = 1×3

1 1 1

B{1}{1}:

ans = 1×3

1 2 3

A{2}:

ans = 1×3

1 2 2

B{2}{1}:

ans = 1

B{2}{2}:

ans = 1×2

2 3

A{3}:

ans = 1×3

1 1 2

B{3}{1}:

ans = 1×2

1 2

B{3}{2}:

ans = 3

[jaah navi]

Could you please help me how to modify the above code

B=cell(size(A));
for i=1:numel(A)
    B{i}=splitapply(@(x){x}, 1:numel(A{i}) ,A{i});
    
    disp("A{" +i+ "}:"), A{i}
    for j=1:numel(B{i})
    disp("B{" +i+ "}{"+j+"}:"), B{i}{j}
    end
    disp ' '
end

when A is [4x3 double; 4x3 double; 4x3 double] instead of [1x3 double; 1x3 double; 1x3 double]