Function 'webread' not supported for code generation Matlab - ThingSpeak - Raspberry Pi

4 visualizzazioni (ultimi 30 giorni)
Hello everybody!
I need to use a Raspberry Pi that get data from a ThingSpeak channel in a standalone configuration, but the problem is that functions ThingSpeakRead and webread are not supported. What can I do?
direccion=['https://api.thingspeak.com/channels/' chId '/feeds.json?api_key=' Read '&results=' cPoints];
datos=webread(direccion);
Function 'webread' not supported for code generation

Risposta accettata

Vinicio Moya
Vinicio Moya il 29 Giu 2021
commandStr = [ 'sudo curl -s "https://api.thingspeak.com/update.json?api_key=' sprintf('%s', Write) '&field1=' sprintf( '%f', dato1 ) ' &field2=' sprintf( '%f', dato2) ' &field3=' sprintf( '%f', dato3) ' &field4=' sprintf( '%f', dato4) ' " ' ];
response = system(mypi, commandStr);

Più risposte (2)

Denis Gurchenkov
Denis Gurchenkov il 29 Giu 2021
Yes, you are right, webread() does not support code generation. As a workaround, you can use coder.ceval functon to call a hand-written C function that opens the connection, reads and decodes the data, and returns the data back to MATLAB code. It is a bit complicated : you would need to maintain two branches in your MATLAB code, one for normal MATLAB execution, the other one for Raspberry Pi, and use coder.target to switch between those.
In order to impelment the C fucntion that does the http read, you can use one of the opensource free HTTP libraries that are available (libcurl is availalbe on raspberry pi?). An alternative is to just invoke curl using system() command. Would this approach work for you?

Vinod
Vinod il 27 Giu 2021
Modificato: Vinod il 27 Giu 2021
Rather than use webread, why not use the blocks in the support package ?

Community

Più risposte nel  ThingSpeak Community

Categorie

Scopri di più su ThingSpeak in Help Center e File Exchange

Prodotti


Release

R2020b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by