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Non-Overlapping Moving Sum

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Suman Dhamala
Suman Dhamala il 27 Giu 2021
Commentato: Suman Dhamala il 27 Giu 2021
Consider any matrix, say Rain=(1:10)'. I want to compute a non-overlapping moving sum with two element.
Rain=1,2,3,4,5,6,7,8,9,10
Compute=1+2,3+4,5+6,7+8,9+10
With traditional movsum command, the moving sum is overlapping elements. I want to evaluate non-overlapping moving sum. Any in-built function? I have tried with loops and all those, it works but in-built function would be fast to compute.

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Star Strider
Star Strider il 27 Giu 2021
Try this —
Rain = [1,2,3,4,5,6,7,8,9,10];
rRain = reshape(Rain, 2, [])
rRain = 2×5
1 3 5 7 9 2 4 6 8 10
sumRain = sum(rRain)
sumRain = 1×5
3 7 11 15 19
These could be combined into one line, however I kept them separate to demonstrate how it works.
.
  6 Commenti
Star Strider
Star Strider il 27 Giu 2021
@Matt J — Thank you! I didn’t think to look in FEX.
Suman Dhamala
Suman Dhamala il 27 Giu 2021
This worked thanks @Matt J and everyone

Accedi per commentare.

Più risposte (1)

Image Analyst
Image Analyst il 27 Giu 2021
Since you have an image, you can do it with blockproc. However it only works with 2-D arrays so you'll have to do it once on each slice, then again along the z direction. I'm attaching some blockproc demos. I haven't done it with a 3-D image so you're on your own but I'm pretty sure it can be done.

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