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how to create an array(1 by 5000) having random values in the range(9-11).

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i have to put the array value as input for sine function, but i guess there are certain limitations for that. it would be great if you could help P.S: new to matlab excuse my immaturity.

Risposte (1)

Attila
Attila il 10 Set 2013
Hi,
Use the uniform distribution function rand(), that outputs values between 0..1 and multiply the values by 2 and add the base 9:
uni = rand(1,5000)*2 + 9
  2 Commenti
sanky kumar
sanky kumar il 10 Set 2013
can i use this array as input for sine function? i guess we'll have some limitations please shed light on this issue
Attila
Attila il 10 Set 2013
Modificato: Attila il 10 Set 2013
There are no limitations. As sine is a periodic function, you can input almost any value. It will return a vector with an identical shape as the input.
results = sin(uni)
plot(1:5000, results, 1:5000, uni)
Is this what you needed?
Edit: MATLAB encourages working with matrices instead of loops. Usually there is a workaround to avoid loops and most of the basic functions can accept vector inputs.

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