Webcam Based Laser Rangefinder

7 visualizzazioni (ultimi 30 giorni)
Yogesh
Yogesh il 19 Set 2013
Commentato: Walter Roberson il 27 Ago 2016
"laser-beam is projected onto an object in the field of view of a camera. This laser beam is ideally parallel to the optical axis of the camera. The dot from the laser is captured along with the rest of the scene by the camera. A simple algorithm is run over the image looking for the brightest pixels. Assuming that the laser is the brightest area of the scene the dots position in the image frame is known. Then we need to calculate the range to the object based on where along the y axis of the image this laser dot falls. The closer to the center of the image, the farther away the object is D = h /tan (theta) where thefa = pfc * rpc + ro ."
can anybody help me regarding this project?
  9 Commenti
Yogesh
Yogesh il 26 Set 2013
I had tried lots of time but not getting and I am very confused now can u please mail the code at yogerocks@gmail.com
Walter Roberson
Walter Roberson il 26 Set 2013
What is your current algorithm, taking into account the hint I gave you ?

Accedi per commentare.

Risposte (2)

Walter Roberson
Walter Roberson il 25 Set 2013
regionprops() can give you the equivalent-radius of a blob. But the actual radius is constant. So now what you need to consider is this: if you have two line segements of the same length, and one is N times further away than the other, then how will the angular size of the two line segments differ?
Hint: the spreading angle from the center of the beam (center of the optical axis) does not change with distance.

ravi
ravi il 20 Feb 2014
this code is a part of rangefinder
<http://www.mathworks.in/matlabcentral/fileexchange/45638-laser-spot-detection>
hope this will help good luck
  2 Commenti
erol karatas
erol karatas il 26 Ago 2016
hi ravi that link doesnt work . could you update links please.
Walter Roberson
Walter Roberson il 27 Ago 2016
The file appears to have been withdrawn or administratively deleted.

Accedi per commentare.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by