Replacing 0 with NaN by indexing into a matrix
4 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Jenny
il 26 Set 2013
Modificato: Azzi Abdelmalek
il 26 Set 2013
I have a data matrix called 'data' of 84761 x 11. (a small selection of the data is attached).
I am able to allocate column variable into arrays e.g. column 10 = WindDirec with DD1 = data(:,10).
I can then replaces the 0 values with NaN by: DD1(DD1==0)=NaN.
Is there a way to do this without first assigning column variables to arrays? I would like to index into the matrix 'data' and replaces all 0 values in column 10 with NaNs.
data(data(:,10)==0)=NaN; replaces the values in the first column with NaN, given by the index provided by where column 10 = 0;
How do I index to column 10 to then replace the 0's with NaNs?
Thank you Jenny
0 Commenti
Risposta accettata
Azzi Abdelmalek
il 26 Set 2013
Modificato: Azzi Abdelmalek
il 26 Set 2013
data(data(:,10)==0,10)=nan
0 Commenti
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Matrices and Arrays in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!