Interpolation within a data table

I have a 12 X 12 table of Z-values, which are found against variable P(1:1:12) and X(25:25:300) as shown in table.I want to get the value of "Z" @ P=10.5 & X=115 via interpolation. your help is appreciated.

6 Commenti

You problem is not clear because if your first column is 1:1:12 then first element in table is 1 and if your first row is 100:25:300 then first element in table is 100. How you have two values at first element in table? Can you please share your table to find out solution
Jan
Jan il 10 Ott 2013
What exactly is "a table"?
am
am il 11 Ott 2013
Sorry, couldn't put it right. Here's the table and I have corrected my question too.
Hi can you send me the table?
Image Analyst
Image Analyst il 12 Ott 2013
Modificato: Image Analyst il 12 Ott 2013
Something is still not correct, despite your claim to have edited it to fix in. You say that the first column is x and is 100:25:300. Yet it seems to be 25:25:300 instead, since the numbers start at 25, not 100. Also the table is 13 columns if the first columns is X and there are 12 columns in addition to that. And if the first row is P and there are 12 rows in addition to that, then there are 13 rows, not 12. So is X and P actually columns/rows in the table as you said? Or are they separate column/row vectors and not part of the 12x12 table?
am
am il 12 Ott 2013
Pardon my ignorance, actually this is some experimental data & yes; X=(25:25:300) and P=1:1:12. The Z values are found against these two variables which is 12x12 table of Z values. So you can say X & P are separate column/row vectors (reference values for Z).

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Risposte (1)

Image Analyst
Image Analyst il 12 Ott 2013

0 voti

Why not just use bilinear interpolation: http://en.wikipedia.org/wiki/Bilinear_interpolation. It's easy, intuitive, and straightforward.

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Richiesto:

am
il 10 Ott 2013

Modificato:

am
il 12 Ott 2013

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