Marker indices for a plot error
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So for whatever reason matlab will not allow me to make a marker index of less then 1. I get an error of
"Value must be a vector of positive integers."
I dont understand the problem. The plot has an x axis scale of very small numbers like .00001-.0001
So naturally my markers must be in that range.
Does anyone know why im getting this error?
plot(time_stamps,smooth(data(1:end,k)),'MarkerIndices',[.01])
1 Commento
Robert Scott
il 15 Ago 2021
Risposte (2)
the cyclist
il 15 Ago 2021
0 voti
The MarkerIndices Name-Value pair is expecting the indices of the data points (e.g. the 1st, 5th, and 10th data point) to place the markers, not the values of those data points.
You might want to use the XTick property of the axes instead.
1 Commento
Robert Scott
il 15 Ago 2021
Star Strider
il 15 Ago 2021
0 voti
‘Indices of data points at which to display markers, specified as a vector of positive integers’
and 0.01 is not an integer.
.
4 Commenti
Robert Scott
il 15 Ago 2021
I will not argue with you about the MATLAB definitions.
x = 0:0.1:2;
y = (x-1).^2;
figure
hp = plot(x, y, 'p-');
hp.MarkerIndices = 15;
hp.MarkerSize = 10;
hp.MarkerFaceColor = 'g';
grid
.
Robert Scott
il 15 Ago 2021
Modificato: Robert Scott
il 15 Ago 2021
In that situation, and you want to put it at a x-value of 0.01, use interp1 and tthe x-values to find the y-values for the markers —
x = -0.5:0.13:2.5;
y = (x-1).^2;
figure
plot(x, y)
xp = 0.01;
yp = interp1(x, y, xp);
hold on
hp = plot(xp, yp, 'p');
hold off
hp.MarkerSize = 10;
hp.MarkerFaceColor = 'g';
grid
If you have the y-values and want to find the x-values, this becomes a bit more complicated, however otherwise straightforward.
.
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