stepinfo 2

15 visualizzazioni (ultimi 30 giorni)
ahmed salama
ahmed salama il 14 Giu 2011
s=tf([1000],[1 3 2 6592 36354 119894 230060 241392 120960]) S = stepinfo(s,'RiseTimeLimits',[0.05,0.95]) S = RiseTime: NaN SettlingTime: NaN SettlingMin: NaN SettlingMax: NaN Overshoot: NaN Undershoot: NaN Peak: Inf PeakTime: Inf it is obvious that this results appears when the denominator is bigger than the forth order what shall i do please answer....

Risposta accettata

Walter Roberson
Walter Roberson il 14 Giu 2011
The documentation shows a 5th order example, so the order must not be the total cause.
It would be worth testing with that example, in case there is something wrong with the calculations on your system.
  2 Commenti
ahmed salama
ahmed salama il 14 Giu 2011
it is a 8th order and there is no problem with my system i think please try the problem in your matlab and see the answers
s=tf([1000],[1 3 2 6592 36354 119894 230060 241392 120960])
S = stepinfo(s,'RiseTimeLimits',[0.05,0.95])
Walter Roberson
Walter Roberson il 14 Giu 2011
Sorry, I do not have that toolbox, so I cannot try that myself.

Accedi per commentare.

Più risposte (0)

Categorie

Scopri di più su Loops and Conditional Statements in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by