Determine for a magic square of order n, the magic sum m. For example m=15 for a magic square of order 3.
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This problem could probably be explained a little better.
This is pretty simple given that there is a built in function to build magic squares. If not, the algorithm to "manually" build a magic square by filling a matrix is already well-known.
sounds interesting!
may be good practice but explanation is confusing!
good practice!
Would be nice to include a image of magic square for those who are not familiar with it
Good problem
I use the sum(n) and it gives me 15 for all the rows or the columns. What is wrong with this, because it does not accept this answer. I also calculated the sum of the first row to get just 15 once, still it does not accept it.