Given four different positive numbers, a, b, c and d, provided in increasing order: a < b < c < d, find if any three of them comprise sides of a right-angled triangle. Return true if they do, otherwise return false .
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See Problem 1550 Can I make a right triangle ?
Thanks Tanya, have enjoyed these.
if (a==2|a==3)
flag=true;
end
The cases are very limited to make such a code valid
Thanks, enjoyed these.
I really liked this problem!
niceee
brainstormed
any insight into handling the case where one of the side lengths is irrational and rounding error in the approximation causes a false negative to be returned?
for example - Test 7
roundup the numbers before comparing
I think for Test-7 , problem creator @Tanya should add "~" to the "flag_correct" part of the line:
assert(isequal(isTherePythagoreanTriple(a, b, c, d),flag_correct))
so it should be changed to :
assert(isequal(isTherePythagoreanTriple(a, b, c, d),~flag_correct))
Pythagorean triplets are taken as positive integers , one of the test case uses irrational number for inputs ! I wish the test creator
@Tanya Morton makes appropriate change as suggested by @Sophia
yeah took me a minute to figure out the rounding bit
The rounding aspect got me really thinking. Exact equality can fail with decimals, so I compared against a small tolerance instead.