Consider the recursion relation:
x_n = (x_(n-1)*x_(n-2))^k
Given x_1, x_2, and k, x_n can be found by this definition. Write a function which takes as input arguments x_1, x_2, n and k. The output should be x_n.
For example, if x_1=exp(1), x_2=pi, n=5, and k=5/9 then:
R = get_recurse(exp(1),pi,5,4/9)
R =
2.31187497992966
Solution Stats
Problem Comments
4 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers85
Suggested Problems
-
Back to basics 17 - white space
280 Solvers
-
Back to basics 21 - Matrix replicating
1809 Solvers
-
What is the distance from point P(x,y) to the line Ax + By + C = 0?
560 Solvers
-
Generate N equally spaced intervals between -L and L
952 Solvers
-
Who has power to do everything in this world?
487 Solvers
More from this Author6
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
is there a story as to why this is "infernal"?
I hate recursion, so it is all infernal to me! Iteration is the way to go...
Test suite could helpfully include n=1 and n=2 tests. I thought that it needed extra complexity to handle these, but @bmtran's top solution shows it doesn't.
I spend a lot of time to get the correct R from the example. The issue is that you say k = 5/9 instead of 4/9 . Just a typo to correct . Thanks