Oxidation State - MATLAB Cody - MATLAB Central

Problem 496. Oxidation State

Difficulty:
(6)
Rate
  • In some chemical compounds, the oxidation state of each atom of hydrogen H is +1.
  • In some chemical compounds, the oxidation state of each atom of oxygen O is -2.
  • The algebraic sum of oxidation states of all atoms in a neutral molecule must be zero.
  • Given a string such as 'sulphuric acid H2SO4', the final token represents the chemical formula of a neutral moledule. This molecule has two atoms of hydrogen, one atom of sulphur and four atoms of oxygen. In this case the oxidation state of sulphur is six, 0-(2*1+4*-2).
  • Another string may be 'sodium hydroxide NaOH'. This molecule has one atom of sodium, one atom of oxygen, and, one atom of hydrogen. In this case, the oxidation state of sodium is one, 0-(-2+1).
  • Each element is denoted by one upper case letter, followed by one or none lower case letter, followed by the number of atoms present, no number means one atom.
  • Assuming above, please find the oxidation state of one atom of the new element in the given formula.
  • Here is a link for additional information and exceptions to these simple rules: Oxidation State.
Solve

Solution Stats

24.36% Correct | 75.64% Incorrect
Last Solution submitted on Feb 26, 2023

Problem Comments

Solution Comments

Show comments
PIVlab surpasses 100K all-time File Exchange downloads
During the past twelve months, PIVlab, a MATLAB Community Toolbox for particle...
Mike Croucher in General
4
8
View Post

Problem Recent Solvers18

Suggested Problems

More from this Author100

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!