A lot of solutions don't work with something like n=5 and m=0
Not at all...
For n-by-n matrix, m=1 if n is odd number.
ur problems are really interesting
This problem has some issues because some pairs (n,m) do not have a solution. For instance, it is impossible to find a matrix such that m = n^2 -1 since a rotation pivot does not move. Moreover, there are floor((n^2)/4) cycles of numbers, and when we match the cycle beginning with its end, it creates two matches. It is possible to do some manipulations to have an m greater than n^2 - floor((n^2)/4), but not always.
My code fails for some of the cases I've mentioned. The current leading solution does better (finding some solutions my code can't), yet sometimes it enters into an infinite loop.
i had no idea this was gonna work :p
Extract leading non-zero digit
DNA N-Gram Distribution
Find perfect placement of non-rotating dominoes (easier)
Add two numbers
Equal to their cube
Formatting currency numbers
Find the stride of the longest skip sequence
Find the Final State of an Abelian Sandpile
Simulate one complete step in the Biham–Middleton–Levine traffic model
The 17x17 Problem
Find the treasures in MATLAB Central and discover how the community can help you!
Choose a web site to get translated content where available and see local events and offers. Based on your location, we recommend that you select: .
You can also select a web site from the following list:
Select the China site (in Chinese or English) for best site performance. Other MathWorks country sites are not optimized for visits from your location.
Contact your local office