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Sandeep Maurya


Attivo dal 2017

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Risposto
Even and Odd parts
n=-10:15; x=[zeros(1,10) ones(1,10) zeros(1,0)]; m=fliplr(n); m1=min([m,n]); m2=max([m,n]); n1=1:length(n); x1=zeros(1,leng...

quasi 7 anni fa | 0

Risposto
convolution of two signals
x=input('Enter x: ') h=input('Enter h: ') m=length(x); n=length(h); X=[x,zeros(1,n)]; H=[h,zeros(1,m)]; for i=1:n+m-...

quasi 7 anni fa | 0