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MOHD UWAIS


Last seen: 17 giorni ago |  Active since 2020

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what will be the multiplication of all c values in loop (in given example), i.e. c1*c2*c3*c4*c5?
a=[1 2 3 4 5]; b=[0 1 0 6 4]; for i=1:5 c=[1 2+a(i); 1*b(i) 5] end

18 giorni ago | 1 answer | 0

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answer

Question


In given example, how can I find multiplication of all c matrices (c1, c2, c3, c4, c5) in a 'for' loop?
a=[1 2 3 4 5]; c=[]; for i=1:5 b=[1 2; 6 5]*a(i); c=[c b] end

18 giorni ago | 1 answer | 0

1

answer

Question


How I can write in code for the Maximum value of 'Y' from left hand side not from right hand side in following figure?

circa 2 mesi ago | 1 answer | 0

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Question


Finding of value coordinate
For example, x=-50:1:50; y=4*x.^2+5; plot(x,y,'*-') How we can find x value corresponding to the minimum value of y.

9 mesi ago | 1 answer | 0

1

answer

Question


How plot to matrices in 3D
How I could plot following matrices in 3D. Here rows and columns of z matrix show to data, which are to plot with x and y. x=1:...

oltre un anno ago | 1 answer | 0

1

answer

Question


Three variables (two independent) 3D plotting
I want to plot B, L, and R mutually at the same time (using both 'for' loop). clear all clc R=[]; for B=-20:20; M=1; ...

oltre un anno ago | 1 answer | 0

1

answer

Question


3D or surface plot
Hi, Please look at my problem. I have a 'A' as dependent variable of two variables B and L. How I could plot in 3D or surface p...

oltre un anno ago | 1 answer | 0

1

answer

Question


How find FWHM for large numbers of plots?
Here simply if i want to write the matlab code to find the fwhm (up to 4 or 5 digits) of like following curve, i have to find x ...

circa 2 anni ago | 1 answer | 0

1

answer

Answered
Interpolate among Datasets so one set matches the other
Thanks for your response. Actually my problem is to find the fwhm(s) of large number of curve like following. So i require the ...

circa 2 anni ago | 0

Question


How can we store many matrices(z) from for loop in a single matrix D(say) in my problem.
x=[1 2 3]; y=1./x; for l=1:3; I=eye(3,3); z=y(l)*I; end

oltre 2 anni ago | 1 answer | 0

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answer