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MOHD UWAIS


Last seen: 3 giorni fa Attivo dal 2020

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Domanda


Data fitting in between following variables x and b for quadratic equation
clear all clc a=[0.450 0.486 0.546 0.589 0.633 0.656]; b=[1.5435 1.536 1.5273 1.523 1.5197 1.5179]; x=1./a.^2;

15 giorni fa | 1 risposta | 0

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Domanda


what will be the multiplication of all c values in loop (in given example), i.e. c1*c2*c3*c4*c5?
a=[1 2 3 4 5]; b=[0 1 0 6 4]; for i=1:5 c=[1 2+a(i); 1*b(i) 5] end

5 mesi fa | 1 risposta | 0

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Domanda


In given example, how can I find multiplication of all c matrices (c1, c2, c3, c4, c5) in a 'for' loop?
a=[1 2 3 4 5]; c=[]; for i=1:5 b=[1 2; 6 5]*a(i); c=[c b] end

5 mesi fa | 1 risposta | 0

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Domanda


Finding of value coordinate
For example, x=-50:1:50; y=4*x.^2+5; plot(x,y,'*-') How we can find x value corresponding to the minimum value of y.

circa un anno fa | 1 risposta | 0

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Domanda


How plot to matrices in 3D
How I could plot following matrices in 3D. Here rows and columns of z matrix show to data, which are to plot with x and y. x=1:...

circa 2 anni fa | 1 risposta | 0

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Domanda


Three variables (two independent) 3D plotting
I want to plot B, L, and R mutually at the same time (using both 'for' loop). clear all clc R=[]; for B=-20:20; M=1; ...

circa 2 anni fa | 1 risposta | 0

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Domanda


3D or surface plot
Hi, Please look at my problem. I have a 'A' as dependent variable of two variables B and L. How I could plot in 3D or surface p...

circa 2 anni fa | 1 risposta | 0

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Domanda


How find FWHM for large numbers of plots?
Here simply if i want to write the matlab code to find the fwhm (up to 4 or 5 digits) of like following curve, i have to find x ...

oltre 2 anni fa | 1 risposta | 0

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Risposto
Interpolate among Datasets so one set matches the other
Thanks for your response. Actually my problem is to find the fwhm(s) of large number of curve like following. So i require the ...

oltre 2 anni fa | 0

Domanda


How can we store many matrices(z) from for loop in a single matrix D(say) in my problem.
x=[1 2 3]; y=1./x; for l=1:3; I=eye(3,3); z=y(l)*I; end

oltre 2 anni fa | 1 risposta | 0

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