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鹏程 张


Last seen: circa 2 anni fa |  Attivo dal 2021

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Facing a unbalanced matrix, such as 3*5000, why someone reduce the computational cost by svd(A*A') .
Computing singular value decomposition is the main computational cost in many algorithms . For a matrix A(m*n) ,if m is much la...

circa 3 anni fa | 1 risposta | 0

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Domanda


How does `svd(A*A')` reduce the computational cost?
Computing singular value decomposition is the main computational cost in many algorithms . For a matrixA(m*n) ,if m is much...

circa 3 anni fa | 1 risposta | 0

1

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