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Syed Mohiuddin


Last seen: 5 mesi fa |  Attivo dal 2022

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Domanda


how to ues the exponentials and derivatives in bvp4c
I have a coupled non-linear differential equations u''-b1*(t')*(u')+(1+b1*t)*[G1*F1*t+G2*F1*p-F3*P]=0; t''-b2*(t')^2+B*F6*(u...

6 mesi fa | 1 risposta | 0

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Domanda


graph is the not plotted as desired because of tolerance level
hi, I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2*dB/dy-2*i*R2*g1*f - g3*G1*y - R4*g1 = 0 (d^2 B)...

6 mesi fa | 1 risposta | 0

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risposta

Domanda


How to get data points from graph
hi, I have graph, i need to prepare a table of the data for x and y terms. How should i get the data points from the enclosed g...

9 mesi fa | 2 risposte | 0

2

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Domanda


Integration using BVP4C
I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2...

oltre un anno fa | 1 risposta | 0

1

risposta

Domanda


How can i get a table values from the program
I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2*dB/dy-2*i*R2*g1*f - g3*G1*y - R4*g1 = 0 (d^2 B)/(dy^...

oltre un anno fa | 0 risposte | 0

0

risposte

Domanda


Unable to meet the tolerance without using more than 1666 mesh points.
I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2*dB/dy-2*i*R2*g1*f - g3*G1*y - R4*g1 = 0 (d^2 B)/(dy^...

oltre un anno fa | 1 risposta | 0

1

risposta

Domanda


I am trying to plot the real part and imaginary part graph using bvp4c and I am getting a straight line,
I have a coupled non-linear differential equations (d^2 f)/(dy^2 )+m2*g2*dB/dy-2*i*R2*g1*f - g3*G1*y - R4*g1 = 0 (d^2 B)/(dy^...

oltre un anno fa | 0 risposte | 0

0

risposte

Domanda


How to get the derivate using bvp4c
I have a coupled non-linear differential equations u''-b1*(t')*(u')+(1+b1*t)*[G1*F1*t+G2*F1*p-F3*P]=0; t''-b2*(t')^2+B*F6*(u')^2...

quasi 2 anni fa | 1 risposta | 0

1

risposta

Domanda


Bvp4c Unable to solve the collocation equations -- a singular Jacobian Encountered
I have a coupled non-linear differential equations u''-b1*(t')*(u')+(1+b1*t)*[G1*F1*t+G2*F1*p-F3*P]=0; t''-b2*(t')^2+B*F6*(u')^2...

quasi 2 anni fa | 1 risposta | 0

1

risposta