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Unable to plot after using fsolve
Ut=0; while Ut<20 cn = @(q1,q2,n0)((Ut.*n0)./(1-cos(2.*pi.*q1)-cos(2.*pi.*q2))); y = @(q1,q2,n0)0.25.*((1+cn...
oltre 10 anni fa | 2 risposte | 0
2
risposteDomanda
Error using fzero " FUN must be a function, a valid string expression, or an inline function object"
I am getting errors while using fsolve or fzero in the following code: U = 1; while U < 20 eq = @(q) 2.*(1-co...
quasi 11 anni fa | 2 risposte | 1
2
risposteDomanda
Error using quad "Error using quad (line 75) The integrand function must return an output vector of the same length as the input vector."
I have edited the code according to answers. Can anyone explain the reason behind the errors and help me correcting the follo...
quasi 11 anni fa | 3 risposte | 0
3
risposteDomanda
Getting errors specifying an anonymous function, integrating and getting points from it.
I want solve the follwing equation and get the values of n0 for different values of U ie. U=1:1:20; <</matlabcentral/answers/...
quasi 11 anni fa | 1 risposta | 0
1
rispostaDomanda
how to use multiple variable in fsolve and plot the corresponding result
I want to plot between 'n0' and 'U'. First I have to get 'n0' in terms of 'U' (for which I used fsolve) eq = @(q) 2*(1 ...
quasi 11 anni fa | 2 risposte | 0
2
risposteDomanda
Unable to plot. Problem with this error "Conversion to double from function_handle is not possible."
function f=snm(~) eq11= @(q1)(2*(1 - cos(2*pi*q1))); hq1= @(q1,U,n0)((eq11)^2 + 2*U*n0*(eq11))^(1/2); ha1= @(q1,U,n0)...
quasi 11 anni fa | 1 risposta | 0
1
rispostaDomanda
Is there any way that I can optimise this code. It takes lot of time to run and for larger iteration like 'nc=10e6' its stops stating runtime error.
clear all %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%Simulation of transmission signal decay from a high Finesse Fabr...
oltre 11 anni fa | 1 risposta | 0
1
rispostaDomanda
I am getting this error- "Vectors must be the same lengths.". Also please explain why its showing this error as I am plotting a funtion with 'x' as variable with defined vector.
clear all rr=0.99997622; % reflectivity of the cavity r=sqrt(rr); finesse=pi.*sqrt(rr)./(1-rr); % fi...
oltre 11 anni fa | 1 risposta | 0
