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Antonio Morales


Attivo dal 2016

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How can I identify a vector subset that meets a given condition?
Given a vector A (please, see attached), how could I find the n-samples vector subset with the smallest range (or standard devia...

quasi 8 anni fa | 0 risposte | 0

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Domanda


How does the following syntax may be shortened and improved?
Given a 12 x 13 matrix, I need to select the row with the greatest value in column 9, every two rows, and create a matrix contai...

quasi 8 anni fa | 2 risposte | 0

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Domanda


Cross-correlation issue: how can I align two signals?
I have two signals A and B (please, see them attached), which have been recorded from different devices with different sampling ...

circa 8 anni fa | 1 risposta | 0

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Domanda


How can I ideantify the least "noisy" baseline periods in a vector?
I have a vector A (see example attached) corresponding to voltage from a strain gauge while testing strength levels in humans, a...

circa 8 anni fa | 0 risposte | 0

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How can I perform matrix calculations within the own matrix?
A_normalised = zeros(size(A)); for ii = 1:6:length(A) for kk = ii:ii+5 A_normalised(:,kk) = (A(:,kk).*100...

circa 8 anni fa | 0

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Domanda


How can I perform matrix calculations within the own matrix?
Hi, I have a 9x612 matrix (A). It consists of 102 variables measured 6 times each (612 columns), in 9 different situations (9...

circa 8 anni fa | 2 risposte | 0

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Domanda


After aligning two signals using xcorr, how to make both signals (varying) lengths equal?
Hello, I am using xcorr to synchronize two signals (S1, S2; from two different devices) of the same event. The function works...

circa 8 anni fa | 1 risposta | 0

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Domanda


Identifying periods of signal above threshold
The code below provides number of "bursts" or periods of activity (300 consecutive points = 0.2 s) above a given threshold. How ...

oltre 8 anni fa | 1 risposta | 0

1

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Domanda


Counting number of bursts
How can I count the number of periods of activity above a certain threshold? I have an EMG signal with some bursts of activi...

oltre 8 anni fa | 1 risposta | 0

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