Azzera filtri
Azzera filtri

How to remove unwanted values from an array?

5 visualizzazioni (ultimi 30 giorni)
Aaron
Aaron il 12 Nov 2013
Commentato: Aaron il 15 Nov 2013
I have one array which looks like the following:
'888888888888888888880001' -40 54 181.012758165326
'888888888888888888880002' -41 155 246.860345748422
'888888888888888888880003' -38 212 297.763557297433
'888888888888888888880004' -42 335 311.493634951638
'888888888888888888880005' -44 461 325.026011960126
'888888888888888888880006' -45 706 328.152463876203
'888888888888888888880007' -41 747 317.266004051673
'888888888888888888880008' -45 941 304.192311286292
'888888888888888888880009' -39 1084 283.163508794566
'888888888888888888880010' -38 1258 313.845862098729
'888888888888888888880011' -33 29 71.2819417558447
'888888888888888888880012' -37 106 187.141362685163
'888888888888888888880013' -31 190 205.110242402620
'888888888888888888880014' -40 301 228.931473501683
'888888888888888888880015' -36 427 336.367180334263
'888888888888888888880016' -35 560 299.892770765854
'888888888888888888880017' -35 656 292.262336479084
'888888888888888888880018' -37 799 285.905285953032
'888888888888888888880019' -40 966 288.908718886324
'888888888888888888880020' -37 1060 292.824547512183
'888888888888888888880021' -30 1209 256.883485018257
I have another array which contains the information in the attached file. A sample of a few rows for formatting are as follow:
'888888888888888888880001' -66 9
'888888888888888888880001' -52 10
'888888888888888888880001' -47 20
'888888888888888888880001' -56 26
'888888888888888888880001' -47 38
'888888888888888888880001' -51 42
'888888888888888888880001' -40 47
'888888888888888888880001' -40 54
'888888888888888888880001' -51 62
'888888888888888888880001' -46 80
'888888888888888888880001' -50 85
'888888888888888888880001' -41 94
'888888888888888888880001' -52 98
'888888888888888888880001' -52 109
'888888888888888888880001' -66 141
'888888888888888888880001' -59 143
'888888888888888888880001' -46 144
'888888888888888888880001' -48 150
'888888888888888888880001' -48 159
'888888888888888888880001' -48 166
'888888888888888888880001' -57 167
'888888888888888888880001' -57 170
'888888888888888888880001' -66 199
'888888888888888888880001' -66 204
'888888888888888888880001' -53 205
'888888888888888888880001' -57 218
'888888888888888888880001' -52 224
'888888888888888888880001' -50 272
'888888888888888888880001' -59 296
'888888888888888888880001' -56 303
'888888888888888888880001' -53 350
'888888888888888888880001' -53 371
'888888888888888888880001' -57 380
'888888888888888888880001' -53 448
'888888888888888888880001' -57 464
'888888888888888888880001' -55 620
'888888888888888888880001' -60 861
See file for full list.
I am wanting to go through each row in the first array, and remove elements in the second array that do not match a criteria. The logic is as follows:
1) For row 1 in the first array, find the row in the second array which has the same first 3 columns.
2) Remove the elements in the second array if the third column in the second array is between the third column in the first array +- the value from the fourth column in the first array.
Example for the provided data:
First Row in the first array:
'888888888888888888880001' -40 54 181.012758165326
Only keep elements in the second array if the third column in the second array is between (54 - 181.012758165326) and (54 + 181.012758165326)....between -127 and 235. The resulting array would be:
'888888888888888888880001' -66 9
'888888888888888888880001' -52 10
'888888888888888888880001' -47 20
'888888888888888888880001' -56 26
'888888888888888888880001' -47 38
'888888888888888888880001' -51 42
'888888888888888888880001' -40 47
'888888888888888888880001' -40 54
'888888888888888888880001' -51 62
'888888888888888888880001' -46 80
'888888888888888888880001' -50 85
'888888888888888888880001' -41 94
'888888888888888888880001' -52 98
'888888888888888888880001' -52 109
'888888888888888888880001' -66 141
'888888888888888888880001' -59 143
'888888888888888888880001' -46 144
'888888888888888888880001' -48 150
'888888888888888888880001' -48 159
'888888888888888888880001' -48 166
'888888888888888888880001' -57 167
'888888888888888888880001' -57 170
'888888888888888888880001' -66 199
'888888888888888888880001' -66 204
'888888888888888888880001' -53 205
'888888888888888888880001' -57 218
'888888888888888888880001' -52 224
Your help would be greatly appreciated.
  2 Commenti
Walter Roberson
Walter Roberson il 13 Nov 2013
Should
1) For row 1 in the first array, find the row in the second array which has the same first 3 columns.
read
1) For row 1 in the first array, find the row in the second array which has the same first 2 columns.
??
Aaron
Aaron il 13 Nov 2013
Modificato: Aaron il 13 Nov 2013
It should be the same first 3 columns. The 3rd column will also be the same. I just want to find that row and then move up and down based on column 4 in the first array

Accedi per commentare.

Risposte (1)

Andrei Bobrov
Andrei Bobrov il 13 Nov 2013
Modificato: Andrei Bobrov il 13 Nov 2013
f = fopen('C:\OneArray.txt');
ca = textscan(f,'%s %f %f %f');
fclose(f);
f = fopen('C:\Example5.txt');
data = textscan(f,'%s %f %f');
fclose(f);
lm = [ca{:,3}-ca{:,4}, ca{:,3}+ca{:,4}];
[lgc,ii] = ismember(data{1},ca{1});
idx=ii(lgc);
funa = @(x){data{3}(x) >= lm(idx(x(1)),1) & data{3}(x) <= lm(idx(x(1)),2)};
p = accumarray(idx,(1:numel(data{1}))',[],funa);
idxout = cat(1,p{:});
d1 = cellfun(@num2cell,data(2:end),'un',0);
d1 = [data{1}, cat(2,d1{:})];
out = d1(idxout,:);
  10 Commenti
Walter Roberson
Walter Roberson il 15 Nov 2013
Andrei will have to answer that; I am not sure what is is trying to do there.
Aaron
Aaron il 15 Nov 2013
I have no clue what most of this means, I am just trying to automate some results and this code makes no sense to me. I think what he posted will work, I will just have to create it as a separate function or something. Thanks for trying.

Accedi per commentare.

Categorie

Scopri di più su Matrices and Arrays in Help Center e File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by