How do i count the no of ones of 3D matrix?
3 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
- I have a big 3-D matrix, say 272*272*272, but contains either 0 or 1; how do i count the number of ones?
- In my project, i need to form a 8*8*8 cube (that why i choose the matrix is 272*272*272). How can i cut this big matrix into 8*8*8 and assign a index for every cube(8*8*8)?
2 Commenti
Image Analyst
il 22 Nov 2013
Why do you need an index? What's wrong with the x,y,z value of the center? What are you going to do? Would you like to use blockproc()?
Risposta accettata
Azzi Abdelmalek
il 22 Nov 2013
Modificato: Azzi Abdelmalek
il 22 Nov 2013
If A is your array
no1=sum(A(:))
For second question
A=rand(272,272,272);
idx2=8:8:272;
idx1=[1 idx2(1:end-1)+1];
n=numel(idx1);
[ii,jj,hh]=ndgrid(1:n,1:n,1:n);
out=arrayfun(@(x,y,z) A(idx1(x):idx2(x),idx1(y):idx2(y),idx1(z):idx2(z)),ii,jj,hh,'un',0);
Più risposte (0)
Vedere anche
Categorie
Scopri di più su Operating on Diagonal Matrices in Help Center e File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!