I need my angles in the [-pi:pi] range instead of [0:2*pi]?
17 visualizzazioni (ultimi 30 giorni)
Mostra commenti meno recenti
Furqan Haider
il 13 Gen 2014
Commentato: Walter Roberson
il 28 Lug 2021
I have an angle in degrees, 225 degrees. Now degtorad(225) function gives me:
>>degtorad(225)
ans =
3.9270 radians
above 'ans' is in the range 0:2pi
I want to know the procedure that i get an answer in the range -pi:pi, as 225 degrees is also equal to -2.3562 radians
225 degree=3.9270 rad
225 degree=-2.3562 rad.
I hope I have made my point clear.
Thank you in advance.
2 Commenti
Walter Roberson
il 28 Lug 2021
Good point, @krishna teja, wrapToPi should work well... at least for people who have the Mapping Toolbox.
Risposta accettata
Walter Roberson
il 13 Gen 2014
R(R > pi) = R(R > pi) - 2*pi;
3 Commenti
Jacob Ward
il 6 Set 2017
True, but putting it inside a while loop would take care of the multiple turns, yes?
temp = 0;
while R != temp
temp = R;
R(R > pi) = R(R > pi) - 2*pi;
end
Più risposte (0)
Vedere anche
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!