How can I read a complex number vector?

Hi, I have this problem. I'm trying to read a complex number vector from a txt file using this structure:

    fid=fopen ('VarName4.txt','r');
    acorrente=fscanf(fid,'%f');
    fclose (fid);

VarName4.txt is a vector 1000x1 like this:

    [0.0141451080390089-0.00224036502008852i
    0.0141451080390089-0.00224036502008852i
    0.0141451080390089-0.00224036502008852i
    0.0141451080390089-0.00224036502008852i...]

Using the structure before, the answer is:

    acorrente =
        0.0141
       -0.0022

Why it doesn't work? Could someone teach me? Thanks a lot!

[José-Luis]

It doesn't work because you are telling fscanf to expect a floating point number. Fscanf won't read in imaginary numbers.

[André Luiz Regis Monteiro]

Hi José-Luis. So, How can I do? thanks.

Answer 1

[Mischa Kim]

André Luiz, this should do:

fid = fopen ('VarName4.txt','r'); 
ii  = 1;
while ~feof(fid)
    acorrente(ii, :) = str2num(fgets(fid));
    ii = ii + 1;
end
fclose(fid);

...read each line of the text file, convert it from string to number and save it in the matrix. The loop will keep reading until the end of the file ( feof ) is reached.

[Mischa Kim]

When using %f you are reading using fixed-point notation, which cuts off the number after some digits. E.g., try,

A = 0.014145108039009 - 0.002240365020089i;
sprintf('%f', A)
ans =
0.014145

[André Luiz Regis Monteiro]

Hi Mischa Kim. Thank you for your attention. It worked! But the numbers are still being cut. Could you help again? Thanks.

original: 0.0141451080390089-0.00224036502008852i answer: 0.0141 - 0.0022i I need a complete number. Thanks a lot.

[Mischa Kim]

That's a formatting setting, the number is saved correctly. In the MATLAB command window put

format long

Answer 2

[JasonLuo]

Use dlmread or textscan https://stackoverflow.com/questions/20538049/reading-complex-data-in-matlab-from-a-file