# Bit stream in to digits

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Raza on 19 Feb 2014
Answered: Jos (10584) on 19 Feb 2014
i have a stream of bits(1 and o), when i save these bit , like i have 128 bits, b1 contains 1 to 10 bits, b2 contain 11 to 20 and so on. Now i got a problem that when i save these bits in b1, b2 , b3 and so on. and want to retrieve, it gives value instead of binary digits, so to solve this issue, i used bitget command but it only support 52 digits, while my requirement is 128
Raza on 19 Feb 2014
i have a stream of bits (1 and 0) , let assume its length is 40. now using for loop i am saving first ten bits in b1, next ten bits in b2 and so on...

Mischa Kim on 19 Feb 2014
Raza, you can retrieve the bit pattern by concatenating the cell strings:
[r, c] = size(b);
bit_stream = [];
for ii = 1:c
bit_stream = strcat(bit_stream,b{ii});
end
disp(bit_stream)
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Raza on 19 Feb 2014
Thanks man, but still got a problem, let me tell u complete detail. i am taking text as a input then i am converting this text into 8 bit binary. and these 8 bits are combined. now i want to separate 128 bits. for example i have text entered "Matlab is good language for coding." and in bits form it is "0101010100010010100100010100100101010101001010..." let assume its length is 256. now i want 128 128 block of bits? i am just stuck in last part

Jos (10584) on 19 Feb 2014
You can split the string into cells
% (smaller) example
MyStr = '10100101010101010010101010101010' ; % a string of arbitrary length
N = 5 ; % the size of each block (in your case 128).
maxN = numel(MyStr)
ix0 = 1:N:maxN
fh = @(X) MyStr(X:min((X+N-1),maxN))
B = arrayfun(fh,ix0,'un',0)
% now B{K} holds the K-th block of N bits of S
MyStrToo = cat(2,B{:})
isequal(MyStrToo, MyStr) % check!