Bit stream in to digits
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i have a stream of bits(1 and o), when i save these bit , like i have 128 bits, b1 contains 1 to 10 bits, b2 contain 11 to 20 and so on. Now i got a problem that when i save these bits in b1, b2 , b3 and so on. and want to retrieve, it gives value instead of binary digits, so to solve this issue, i used bitget command but it only support 52 digits, while my requirement is 128
Accepted Answer
Mischa Kim
on 19 Feb 2014
Raza, you can retrieve the bit pattern by concatenating the cell strings:
[r, c] = size(b);
bit_stream = [];
for ii = 1:c
bit_stream = strcat(bit_stream,b{ii});
end
disp(bit_stream)
More Answers (1)
Jos (10584)
on 19 Feb 2014
You can split the string into cells
% (smaller) example
MyStr = '10100101010101010010101010101010' ; % a string of arbitrary length
N = 5 ; % the size of each block (in your case 128).
maxN = numel(MyStr)
ix0 = 1:N:maxN
fh = @(X) MyStr(X:min((X+N-1),maxN))
B = arrayfun(fh,ix0,'un',0)
% now B{K} holds the K-th block of N bits of S
MyStrToo = cat(2,B{:})
isequal(MyStrToo, MyStr) % check!
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