is it possible to get index of reshaped matrix

i have a matrix A of size 1*120 and reshaped it to matrix B of size 10*12..... is it possible to get the index values of where the value of A has gone to B in a matrix C of size 1*120....

Answer 1

[Iain]

The functions ind2sub and sub2ind, give you a more general way of doing it, which expands to more dimensions...

[Elysi Cochin]

if i have a matrix

 A = [22 33 44 55 66 77]

and i reshape it to

 B = [22  44  66 
      33  55  77]

i want C = [1 2 1 2 1 2].... how to do it...

[Iain]

 temporary = 1:numel(A);
 C = mod(temporary ,size(B,1))+1;

Answer 2

[Jos (10584)]

A short story of LINEAR vs. SUB indexing:

A = [22 33 44 55 66 77]
B = reshape(A,2,[])

    numel(A),numel(B)  % the same number of elements
    size(A), size(B)   % but with different sizes

% However, reshaping does not change the intrinsic order of the elements inside an array.
% This intrinsic order is used by linear indexing:
  LinIdx = 3   % any value between 1 and numel(A)
  A(LinIdx), B(LinIdx)

% Linear indices correspond to different rows and columns for A and B,
% due to the different shapes between A and B:
  LIDX = 1:numel(A) % all linear indices
  [rowA, colA] = ind2sub(size(A), LIDX)
  [rowB, colB] = ind2sub(size(B), LIDX)

rowB is what you call C

Answer 3

[Mischa Kim]

This would do

 An     = 1:length(A);
 nr     = 10;
 C(:,1) = floor((An-1)/nr) + 1;
 C(:,2) = An' - nr*(C(:,1)-1);

where the first and second cols of C are the column and row indices.

Answer 4

[Sagar Damle]

C and C1,both are one and the same thing.

A = [22 33 44 55 66 77] 
 B = reshape(A,2,[])
 temp = 1:size(B,1)
 C = repmat(temp,1,size(B,2))
 C1 = kron(  ones(1,size(B,2))  ,  temp  )

[Elysi Cochin]

thank you all for the answers.....