Azzera filtri
Azzera filtri

why fplot take more time to run here?

1 visualizzazione (ultimi 30 giorni)
Jatin89
Jatin89 il 20 Mar 2014
Modificato: Star Strider il 20 Mar 2014
Here is the line of code. my Question is why does #2 take more time than #1. 1) fplot('sin(x)',[0 2*pi],1e-2) 2) fplot('sin(x)',[0 2*pi],1e-6) Thanks

Risposte (1)

Star Strider
Star Strider il 20 Mar 2014
Modificato: Star Strider il 20 Mar 2014
From the documentation for fplot:
-----
fplot(fun,limits,tol) plots fun using the relative error tolerance tol (the default is 2e-3, i.e., 0.2 percent accuracy).
. . .
fplot uses adaptive step control to produce a representative graph, concentrating its evaluation in regions where the function's rate of change is the greatest.
-----
It seems to me that a tolerance of 1E-6 would require more steps — and therefore more time to execute — than a tolerance of 1E-2.

Categorie

Scopri di più su Polar Plots in Help Center e File Exchange

Tag

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by