- a 00 transition yields 0
- a 01 transition yields 0
- a 10 transition yields -k
- a 11 transition yields +k
decoding of bitstream in image processing?
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hi, Suppose for t=8, I have x=[1 1 1 0 0 0] and decoded data is stored in p. So first I initialize p=zeros(1,4); now for decoding it if x(1)=1 && x(2)=1, then I should get re(1)=3*t/2 and then if x(3)=1 && x(4)=0 then I should get re(2)=-3*t/2 and x(5)=0 so re(3)=0 and x(6)=0 so re(4)=0. How can I do it by programming. Can anyone please help me?
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DGM
il 27 Ott 2024 alle 8:21
There are four possible transition states, but only three are (confusingly/incorrectly) described. Assuming the following:
where k is 3*t/2, then:
t = 8;
x = [1 1 1 0 0 0];
dx = diff(x);
hihi = ~dx & x(2:end);
hilo = dx < 0;
re = (hihi - hilo)*3*t/2
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