Decrementing step for loop I matlab

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Dennis M il 24 Ago 2021
Commentato: Dennis M il 24 Ago 2021
y = zeros(1,12);
for i = 1:12
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = 10:-1:2
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
Good Day,
May I ask how can I insert the start and stop variable on above code? for example I want to start in 17 to 30 or 15 to 2 with decrementing step.
Thanks and Regards,
Dennis
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Awais Saeed il 24 Ago 2021
Modificato: Awais Saeed il 24 Ago 2021
% start, step, and end points
starty = 1;
endy = 12;
startx = 10;
endx = 2;
decrement = -1;
y = zeros(1,12);
for i = starty:endy
y(i+1) = y(i) + ((5 - (4/50)*y(i)));
end
y
x = zeros(1,10);
for i = startx:decrement:endx
x(i-1) = x(i) + ((5 + (4/50)*x(i)));
end
x
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Awais Saeed il 24 Ago 2021
Modificato: Awais Saeed il 24 Ago 2021
I am having difficulty in trying to understand your question. Do you want your first loop to start from 17 or 20 and end at 30 or 45? If that is the case just do
starty = 17;
endy = 30;
Same goes for the second loop. 'starty' and 'endy' are variables.
Dennis M il 24 Ago 2021

<<

>> There was error when I change the variables, I have to change also the y = zeros(1,12); defend on the length. I want a loop that the output is like this (10 20 29 38 47 56 65 and so on) and (80 70 61 53 46 40 35 and so on) same in negative (-10 -20 -29 -38 -47 -56 -65 and so on) and (-80 -70 -61 -53 -46 -40 -35 and so on)

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